[En-Nut-Discussion] [Understand compilation process] avr-objcopy -R .eeprom

[Rodrigue]

Hello,

When I compile "simple" project. The following commands are executed:
avr-objcopy -R .eeprom -O ihex simple.elf simple.hex
avr-objcopy -O binary simple.elf simple.bin

The first command removes the .eeprom section form simple.elf and converts
the rest of the file in ihex format (is it Intel Format?). Why remove this
section? How to write the eeprom section? If I have a variable like this in
my software:
static const char my_string[] __attribute__ ((section(".eeprom"))) = "This
data will be loaded into EEPROM";
What's happening?

The second command converts simple.elf file in binary format which is not
used after, so I don't understand why it's generated?
make -k burn 
avrdude -p atmega128 -P com1 -c stk500v2 -V -U flash:w:simple.hex 

Thanks in advance!
Rodrigue

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